If $\sin \theta + \sqrt{3} \cos \theta = 6x - x^2 - 11$,where $x \in R$ and $0 \le \theta \le 2\pi$,then the equation has a solution for:
- Aone value of $x$
- Btwo values of $x$
- Cinfinite values of $x$
- Dno value of $x$
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